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A = B * (1+C)^D - E * ((1+C)^D-1) / C
A B and D are fixed
Solve for C
E is free
A = B * (1+C)^D - E * ((1+C)^D - 1/ C)
Um, mate, given those restrictions, any non-zero value of C is a solution, short of a handful of singularity cases.
Let A B D and C be arbitrary numbers, with C not equal to 0, and (1+C)^D not equal to 1/C
Then:
Let
X := A
Y := B * (1+C)^D
Z := (1+C)^D - 1/ C
Then:
X = Y - E * Z
or
E = (Y-X)/Z
QED
I think I have the wrong question.
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Last edited by JHVH : 10-29-4004 BC at 09:00 PM. Reason: Time for a rest.
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