Quote:
Originally posted by KungFuGuy
lol- just imagine a physics porno. or porno physics.
imagine bringing an instructional video to class?
"now...you'll notice that my ejaculate is exiting my penis at an angle of about 38 degrees with a velocity of...."
"now here's a little quiz question- If i'm humping forward with a velocity of 1 m/s at the time of release how much further will my ejaculate go than if i was humping backwards at the same speed?"
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Assuming that we are measuring distance from the initial launch height, velocity is 1 m/s, and the angle is 38*, then he would ejaculate a distance of .099 meters during initial ejaculation (using the equation X-Xo=(Vo^2)/g*sin(2(theta)). If you assume the same initial velocity in the reverse hump position, and that the angle did not change, then the distance of the ejaculate would be .099-(distance of reverse hump). If you want to assume that the intial velocity of his hump changed, then we would need more determining factors, such as the mass of the semen, and the distance the penis travelled backwards during the reverse thrust. Then you could solve it using force equations instead of projectile motion.
This is what I get for being a fucking Engineering major.