[C]Celsius & Farenheit Conversion Table

[zero2]

I kind of have this one worked out, somewhat. What I'm trying to do, is create a table using a for loop. The table will have Celsius from 0 to 100 and a table for Farenheit 32 to 212.

Here's what I got:

/* This program prints out a conversion table for Celsuis to Farenheit (0 to 100) and Farenheit to Celsius (32 to 212).
Written by:

*/

#include <stdio.h>

#define Conversion_Factor (100.0 / 180.0)

int main (void)
{
/* Local Definitions */
	float x;
	float y;
    
/* Statements */
printf(" Farenheit Conversion Table\n");
for ( x = 0; x <= 100; x++)
{
/* Centigrade to Farenheit */
printf("%.2f\t", (Conversion_Factor * x) + 32);
}
printf("\n");

return 0;
}
/* main */

/* Results */

The results I get are the following, which is almost right except my ending value doesn't quite make it to 212, for some odd reason.

 Farenheit Conversion Table
32.00   32.56   33.11   33.67   34.22   34.78   35.33   35.89   36.44   37.00
37.56   38.11   38.67   39.22   39.78   40.33   40.89   41.44   42.00   42.56
43.11   43.67   44.22   44.78   45.33   45.89   46.44   47.00   47.56   48.11
48.67   49.22   49.78   50.33   50.89   51.44   52.00   52.56   53.11   53.67
54.22   54.78   55.33   55.89   56.44   57.00   57.56   58.11   58.67   59.22
59.78   60.33   60.89   61.44   62.00   62.56   63.11   63.67   64.22   64.78
65.33   65.89   66.44   67.00   67.56   68.11   68.67   69.22   69.78   70.33
70.89   71.44   72.00   72.56   73.11   73.67   74.22   74.78   75.33   75.89
76.44   77.00   77.56   78.11   78.67   79.22   79.78   80.33   80.89   81.44
82.00   82.56   83.11   83.67   84.22   84.78   85.33   85.89   86.44   87.00
87.56
Press any key to continue

As for the other way around Farenheit to Centigrade, I have coded it the following way, but when I added it to the end of the previous code, it stops and doesn't execute.

printf("Centigrade Conversion Table\n");
for( y = 32; y <= 212; y++)
{
/* Farenheit to Centigrade */
printf("%.2f\t", Conversion_Factor * (y - 32);
}
printf("\n");

TIA, for any help or suggestions that you can provide.

[Pragma]

#include <stdio.h>
#define CFRATIO (9.0/5.0)
#define FCRATIO (5.0/9.0)

int main (void)
{
/* Local Definitions */
  int i;  
        
  /* Statements */
  printf("Celcius -> Farenheit Conversion Table\n");
  for ( i = 0; i <= 100; i++) {
    /* Centigrade to Fahrenheit */
    printf("%.2f\t", (CFRATIO * i) + 32);
    if( ( (i+1) % 10 ) == 0 ) {
      printf("\n");
    }
  }
  printf("\nFahrenheit -> Celcius Conversion Table\n" );
  for ( i = 32; i <= 212; i++) {
    /* Fahrenheit to Centigrade */
    printf("%.2f\t", (i - 32) * FCRATIO );
    if( ( (i+1) % 10 ) == 0 ) {
      printf("\n");
    }
  }
  printf("\n");
  return 0;
}

Cleaned up your code a bit and fixed a few bugs.

[zero2]

I just ran it and it works .

The only thing that I don't understand is this statement, if( ( (i+1) % 10 ) == 0 )? Can you tell me what this does?

Thanks again for your help

--zero2

[welshbyte]

It means "if (i + 1) is a multiple of ten..."

[Pragma]

It's just to make printing the output appear in nice columns of 10. Nothing too important, look up the modulus operation.

[zero2]

Oh now I see it, ok.