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Complex numbers and exponites
If Z is a complex number how would I calculate:
Z^Z. |
Quote:
If I remember correctly there is a family of solutions. Do you know how to raise a complex number to a real power? Do you know how to raise a real number to a complex power? |
This might be helpful to you... http://www.math.toronto.edu/mathnet/...omplexexp.html
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i = e^(pi*i*(1/2 + 2*k))
i^(a+b*i) = e^(pi*i*(1/2 + 2*k))^(a+b*i) = e^(pi*(1/2 + 2k)*(-b+a*i)) = e^(-pi*b*(1/2+2k) + pi*i*a*(1/2+2k)) = e^(-pi*b*(1/2+2k)) * e^(pi*i*a*(1/2+2k)) If b is not 0, this is a set of points arranged in a spiral. The magnatude of each point is e^(-pi*b*(1/2+2k)) while the angle is e^(pi*i*a*(1/2+2k)) If a is rational, the result takes on finitely many angles. If a is irrational, the angles form a dense net. Ie, if b is 0 and a is irrational, then the set of roots is dense on the complex unit circle. If b is not zero, then the set of roots spirals from 0 out to infinity. This seems less than useful. You could identify a particular root as the primary root. |
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