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|  01-31-2004, 02:06 PM | #1 (permalink) | 
| Swashbuckling Location: Iowa...sometimes | 
				
				Trig help -  FAST AND HARD!!!
			 I have to find where these two functions intersect. g(x) = sin(2x) & f(x) = sin(x) so sin(2x) = sin(x) How do I solve for x? need exact value, not decimal. THANK YOU  
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|  01-31-2004, 04:28 PM | #4 (permalink) | |
| Swashbuckling Location: Iowa...sometimes | Quote: 
 Thanks. And yeah, I SHOULD know the identity, but havn't had trig in years. (I'm actually in calc, rotating regions around a line and taking the integral to find the volume of da' soild) fun fun 
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|  01-31-2004, 09:52 PM | #5 (permalink) | 
| Without Wings Location: Australia | sin(2x) = 2sin(x)cos(x) cos(2x) = 2cos^2(x) - 1 cos(2x) = 1 - 2sin^2(x) cos(2x) = cos^2(x) - sin^2(x) tan(2x) = 2tan(x) / 1 - tan^2(x) sin(x+y) = sin(x)cos(y) + cos(x)sin(y) sin(x-y) = sin(x)cos(y) - cox(x)sin(y) cos(x+y) = cos(x)cos(y) - sin(x)sin(y) cos(x-y) = cos(x)cos(y) + sin(x)sin(y) tan(x+y) = tan(x) + tan(y) / (1 - tan(x)tan(y)) tan(x-y) = tan(x) - tan(y) / (1 + tan(x)tan(y)) sin^2(x) = 0.5 - 0.5cos(2x) cos^2(x) = 0.5cos(2x) - 0.5 i think they're all correct, havent had to think about any of it for 4months.. hope they are, that'd mean i'd have less to worry about this year | 
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| Tags | 
| fast, hard, trig | 
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