Tilted Forum Project Discussion Community  

Go Back   Tilted Forum Project Discussion Community > The Academy > Tilted Knowledge and How-To


 
 
LinkBack Thread Tools
Old 09-10-2003, 12:55 PM   #1 (permalink)
The GrandDaddy of them all!
 
The_Dude's Avatar
 
Location: Austin, TX
Limits

I'm lost at how to do this problem.




Any help would be appreciated.
__________________
"Luck is what happens when preparation meets opportunity." - Darrel K Royal

Last edited by The_Dude; 09-10-2003 at 03:40 PM..
The_Dude is offline  
Old 09-10-2003, 08:45 PM   #2 (permalink)
Crazy
 
Location: Salt Lake City
I stared at it for a full minute before I realized it wasn't a 5-part problem, it's multiple choice. The answer is #1. Just plug f(x) into that first equation (which is just the definition of the derivative) and you'll get a answer yourself easy enough.
__________________
---<>---^^---<>---^^---<>---
---^^---<>---^^---<>---^^---
---<>---^^---<>---^^---><---
GreasyP is offline  
Old 09-10-2003, 09:22 PM   #3 (permalink)
Swashbuckling
 
Location: Iowa...sometimes
Once you learn the Chain Rule, you will be pissed that your professor didn't teach you it the first day of class. It makes solving those problems possible in seconds.
__________________
Watch More TV
BuddyHawks is offline  
Old 09-10-2003, 10:57 PM   #4 (permalink)
TIO
Addict
 
TIO's Avatar
 
Location: The Land Down Under
Have you done differentiation yet? That limit is just first-principles differetiation of f(x). Works for any (differentiable) f(x).
__________________
Strewth
TIO is offline  
Old 09-10-2003, 11:21 PM   #5 (permalink)
Upright
 
Hey, let's see if I can remember how to do it, the answer that was previously mentioned (#1) is correct, and it can easily be solved by the chain rule[which is second nature, once you learn it]. However, what you are given here is the formal definition of a limit. To see how to get the answer of 6x+4 here are the complete mathematical steps:

Ok the first part says f(x+h), so that means take your f(x) equation and h to every x term you see:

3(x+h)^2 + 4(x+h) + 2


and that's basically it, now apply the equation

lim as h->0 f(x+h) - f(x) / h

so... we have:

lim h->0 (3(x+h)^2 + 4(x+h) + 2 - [3x^2 + 4x + 2]) / h

lim h->0 (3x^2 + 6xh + 3h^2 + 4x + 4h + 2 - [3x^2 + 4x + 2]) / h

now, perform some cancellations and you have:

lim h->0 (6xh + 3h^2 + 4h) / h now.. you see a common factor of h, which can also be cancelled, so you're left with:

lim h->0 (6x+3h+4)
ok, you may be saying what!?! that's not the answer.. now, you simply plug in 0 for h, so you have as a final answer: f`=dy/dx = 6x + 4

Hope this clarifies your problem and closes the book on this thread :-)

P.S. Make sure you continuously write lim h->0 for each step as I did, teachers are notorious for taking points off for not including that, since it is a formal definition of a limit.
sieger35 is offline  
Old 09-11-2003, 07:26 AM   #6 (permalink)
TIO
Addict
 
TIO's Avatar
 
Location: The Land Down Under
Quote:
Originally posted by sieger35
However, what you are given here is the formal definition of a limit.
No, that's the formal (or, more accurately, the first principles) definition of a derivative.
__________________
Strewth
TIO is offline  
Old 09-11-2003, 07:57 AM   #7 (permalink)
Upright
 
Yes, you are correct, I made the wrong statement (hehe, sorry it was almost 4 am when I posted :-) ). However, I made the right notation of f`=dy/dx= 6x+4
sieger35 is offline  
Old 09-12-2003, 11:37 AM   #8 (permalink)
Insane
 
man, does this bring back memories. bad bad, horrible memories...
inkriminator is offline  
Old 09-12-2003, 01:53 PM   #9 (permalink)
Addict
 
that made me tired, now im reliving my deficient past
stldickie is offline  
Old 09-12-2003, 03:53 PM   #10 (permalink)
Know Where!
 
MacGnG's Avatar
 
http://mathworld.wolfram.com/Derivative.html

THIS IS THE SHORT WAY (sorta)
3x^2 + 4x + 2
ax^n + bx + c --- a,b,c, are constants

(n*a)X^(n-1) +b --- c is a constant so it becomes 0
(3*2)X^(2-1) +4

=6X + 4
MacGnG is offline  
Old 09-12-2003, 11:27 PM   #11 (permalink)
Tilted
 
Location: Tucson, AZ
I love calculus

Ahh.. shortcuts are the world. Beautiful Integrating Factors.. Blah Blah Blah...
__________________
University of Arizona
Tucson, AZ
Computer Engineering
quantumburnz is offline  
Old 09-16-2003, 07:56 AM   #12 (permalink)
Insane
 
Location: The Internet
Some very good answers here.

Change f(x)= 3x^2 + 4x + 2 into "box"

Then plug "box" into the differentiation formula in place of "x".

you get: (box - h) - box / h

now simplify the terms using the real value of "x" (ie. 3x^2 + 4x + 2)

Later on, you will learn "the power rule" which simply states:

where f(x)= x ^ 3
f ' (x)= [exp] x ^ [exp - 1]

ie. f ' (x) = 3x^2

.. much better

In your case:

f(x)=3x^2 + 4x + 2

f ' (x)=6x + 4x + 0

PS: you will notice that the derivitave of any "real number" is always 0
__________________
rm -f /bin/laden
Sapper is offline  
Old 09-17-2003, 10:56 PM   #13 (permalink)
Devils Cabana Boy
 
Dilbert1234567's Avatar
 
Location: Central Coast CA
oh god i hate calc
__________________
Donate Blood!

"Love is not finding the perfect person, but learning to see an imperfect person perfectly." -Sam Keen
Dilbert1234567 is offline  
Old 09-18-2003, 05:32 AM   #14 (permalink)
Insane
 
Location: The Internet
Lol. It's not that bad ... really ...

Honestly, I used to fear math .. until I decided - fuck it! I will work my ass off and actually master the topic. Incidently, I no longer have an ass .. but I do understand calculus.

__________________
rm -f /bin/laden
Sapper is offline  
Old 09-18-2003, 10:05 AM   #15 (permalink)
TIO
Addict
 
TIO's Avatar
 
Location: The Land Down Under
uh...how much of it, Sapper? Multivariate? Manifolds? If so, there's a senior lecturer around here who would love for you to explain it to him!

There's a lot more to Calc than derivatives and the kind of integrals you encounter in grade school!
__________________
Strewth
TIO is offline  
Old 09-18-2003, 12:25 PM   #16 (permalink)
Insane
 
Location: The Internet
TIO, a tad anal or what? Wow.

You obviously can not appreciate the notion of understanding something. Not that it really matters - what you think is of no consequence to me.

PS: Because you seem to lack fundamental social skills, I will take this to mean that you also lack fundemental logic skills. You should take special note that I said: "I will work my ass off and actually master the topic" and not "I will work my ass off and actually have mastered the topic".
__________________
rm -f /bin/laden
Sapper is offline  
Old 09-18-2003, 01:13 PM   #17 (permalink)
Invisible
 
yournamehere's Avatar
 
Location: tentative, at best
Heh heh - wait till 3 semesters from now, when your Differential Equations professor informs you that up until now, you've been doing it all backwards.
__________________
If you want to avoid 95% of internet spelling errors:
"If your ridiculous pants are too loose, you're definitely going to lose them. Tell your two loser friends over there that they're going to lose theirs, too."
It won't hurt your fashion sense, either.
yournamehere is offline  
Old 09-18-2003, 05:11 PM   #18 (permalink)
Insane
 
Location: The Internet
Lol. That'll be a great day
__________________
rm -f /bin/laden
Sapper is offline  
 

Tags
limits


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On



All times are GMT -8. The time now is 11:17 AM.

Tilted Forum Project

Powered by vBulletin® Version 3.8.7
Copyright ©2000 - 2024, vBulletin Solutions, Inc.
Search Engine Optimization by vBSEO 3.6.0 PL2
© 2002-2012 Tilted Forum Project

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54