Thread: Algebra
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Old 10-20-2003, 10:38 PM   #2 (permalink)
lordjeebus
この印篭が目に入らぬか
 
Location: College
consider this:

k = whatever
for any non-zero x, x^n = x^(n+k-k) = (x^(n+k))/(x^k)
for instance, x squared is the same as x cubed over x.

when n = 0, x^0 = (x^(0+k)/(x^k) = (x^k)/(x^k) = 1, because anything divided by itself is one.

hmm. does anyone have a cleaner explanation? i have a feel for why x^0 = 1 but it's hard for me to articulate.
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