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That would work if it's 2xe^(-2x), but it looks like it's (2xe)^(-2x).
ps. dunno how blizzak got his answer--i tried that site and came up with no answer. (looks like a neat site though!) I also wonder if this is possible without numerical methods.
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oh baby oh baby, i like gravy.
Last edited by rsl12; 10-13-2005 at 11:16 AM..
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