Quote:
Originally Posted by keyshawn
so far i have:
Code:
[infinity symbol] [2^k] (-1)^(k+1)
[Sigma symbol] _____________________
K= 1 10
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Almost there, but like you say the formula you have now will give you .2-.4+.8 ...
Try this:
Code:
[infinity symbol] [2^(2k+1)] (-1)^(k)
[Sigma symbol] _____________________
K= 0 10
I'm a bit rusty and working quickly but that should work.