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Dumb Probability Question
The question is not dumb, i just don't like math.
A box contains two defective Christmas tree lights that have inadvertently mixed with eight nondeffective lights. IF the lights are selected one at a time without replacement and tested until both defective lights are fund, what is the probability that both defective lights will be found after three trials.
I think that you work it out like this to find the answer, but i am not sure:
(2/10)*(2/9)*(1/8)=(1/180)
Thanks
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