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Probability Question I am stuck on
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10-30-2004, 09:08 PM
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molloby
Tilted
Location: Sydney, Australia
I think I've got it:
There are 80C8 unique ways of choosing 8 balls from 80 and 70C8 ways of choosing 8 balls from 70. So:
Number of with defects = Total number of choices - number of choices without defects
= 80C8-70C8
=19,547,718,623
Enjoy.
molloby
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