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Probability Question I am stuck on
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10-30-2004, 08:20 PM
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molloby
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Location: Sydney, Australia
All right. X~B(8,1/8)
P(X/=0) = 1-P(X=0) = 1-(7/8)^8 = 0.656391
Therefore from 10 samples the expected number with at least one defective bulb is 6.56391 or 7.
molloby
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